By NEAS - 8/6/2018 9:17:53 PM
MS Module 4 t values and confidence intervals practice exam questions
(The attached PDF file has better formatting.)
A statistician estimates the population mean for a normal distribution from a sample of 6 points. The 99% confidence interval for the population mean is (0, 1.78)
Question 4.1: Critical t value
What is the critical t value for a 99% confidence interval from a sample of 6 points?
Answer 4.1: 4.032 (table look-up)
Question 4.2: Standard error of estimated mean
What is the standard deviation of the sample / the square root of the number of observations?
Answer 4.2: (1.78 – 0) / (2 × 4.032) = 0.2207
(width of confidence interval = 2 × t value × σ/√N)
Question 4.3: Standard deviation of sample
What is the standard deviation of the sample?
Answer 4.3: 0.2207 × 60.5 = 0.5406
(width of confidence interval = 2 × t value × σ/√N)
Question 4.4: Critical t value
What is the critical t value for a 95% confidence interval from a sample of 6 points?
Answer 4.4: 2.5706 (table look-up)
Question 4.5: Estimated mean
What is the estimated mean of the population?
Answer 4.5: (1.78 – 0) / 2 = 0.89
(mean = mid-point of confidence interval)
Question 4.6: Confidence interval
What is the 95% confidence interval for the population mean?
Answer 4.6: The confidence interval is 0.89 ± 0.2207 × 2.5706:
● lower bound: 0.89 – 0.2207 × 2.5706 = 0.323
● upper bound: 0.89 + 0.2207 × 2.5706 = 1.457
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