By NEAS - 7/2/2024 4:41:16 PM
MS Module 9 Difference of means for small samples practice exam questions
(The attached PDF file has better formatting.)
Samples from two groups have the following samples sizes, means, and standard deviations:
Group Sample Size Sample Mean Sample SD
Group 1 5 12 1.1
Group 2 7 15 1.4
μ1 = the mean of Group #1; μ2 = the mean of Group #2.
The null hypothesis is H0: μ1 = μ2; the alternative hypothesis is Ha: μ1 ≠ μ2.
Question 9.1: Variance of estimated mean
What is the variance of the estimated mean of each group?
Answer 9.1: variance of the estimated mean = (standard deviation)2 / number of observations
● Group 1: 1.12 / 5 = 0.242
● Group 2: 1.42 / 7 = 0.280
Question 9.2: Variance of estimated difference of group means
What is the variance of the estimated difference of the group means?
Answer 9.2: 0.242 + 0.280 = 0.522
(variance of the estimated difference of the group means = sum of variances of estimated group means)
Question 9.3: Standard deviation of estimated difference of group means
What is the standard deviation of the estimated difference of the group means?
Answer 9.3: 0.5220.5 = 0.7225
(standard deviation = square root of the variance)
Question 9.4: Degrees of freedom
What are the degrees of freedom for a t test of each group’s mean?
Answer 9.4: Degrees of freedom = number of observations – 1
● Group 1: 5 – 1 = 4
● Group 2: 7 – 1 = 6
Question 9.5: Degrees of freedom
What are the degrees of freedom for a t test of the difference of the group means?
Answer 9.5: The approximate degrees of freedom is
(s21/m + s22/n)2 / (s21/m)2/(m-1) + (s22/n)2/(n-1) =
(variance of group 1 mean + variance of group 1 mean)2 /
(square of variance of group 1 mean / (group 1 observations – 1)
+ square of variance of group 2 mean / (group 2 observations – 1) ) =
(0.242 + 0.280)2 / (0.2422 / (5 – 1) + 0.282 / (7 – 1) ) = 9.834
We truncate the degrees of freedom to 9.
Question 9.6: t value for difference of group means
What is the t value for a 90% two-sided confidence interval of the difference of the group means?
Answer 9.6: 1.833
(the t value for a 90% two-sided confidence interval is the t value for a 5% one-tailed test with 9 degrees of freedom)
Question 9.7: Confidence interval
What is the 90% two-sided confidence interval of the difference of the group means (μ1 – μ2)?
Answer 9.7: Confidence interval = (μ1 – μ2) ± t value × standard deviation of the difference of the group means
● lower bound: (12 – 15) – 1.833 × 0.7225 = -4.324
● upper bound: (12 – 15) + 1.833 × 0.7225 = -1.676
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