TS Module 5: Stationary processes HW


TS Module 5: Stationary processes HW

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CalLadyQED
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@dom2114: Thank you. I had figured that out myself, but appreciate you mentioning it. I was making a different mistake and started to doubt that part that I had done right.

@djfobster: I got the same answer for C.

@DMW: It's not -0.345/9. gamma0 does NOT equal 9. sigma-squared = 9.
DMW
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MY BAD!  Yep, you're right.  I see sigma^2 and get all excited.  sigma^2 <> var(Y_t)

   -    Dave
minnie53053
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yeah, I get -0.0368 too.

COV(Yt,Yt-2)=-0.345.

rho2=COV(Yt,Yt-2)/(VAR(Yt)*VAR(Yt-2))^0.5=-0.345/9.375=-0.0368


LIAPP
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Question on part C...

Wouldn't the conventional equation for correlation not work in this scenario since we cannot assume stationarity? Stationarity, by definition, depends only on lag and not absolute time, but we can see that because the terms do not follow the same pattern for every lag of 2, then the correlation assumption doesn't hold.

Given the explanation for Psi on page 55, the coefficient on the first expression isn't non-existent, but is simply Phi^0. This would lead to a coefficient pattern of +, +, -, +, -, +, -, ... , wherein the correlation between e(t) and e(t-2) would be negative, but all other intervals would be positive.

I'm not sure whether I'm missing something, or if the equation is given later in the book, or if the answer is undefined. Any help is appreciated.


nacho
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LIAPP,

If you work out what minnie53053 posted just above, it works out as she has written:

rho2=COV(Yt,Yt-2)/(VAR(Yt)*VAR(Yt-2))^0.5=-0.345/9.375=-0.0368.

I worked out the covariance to be phi^2*Var(e)*(-1+phi^2+phi^4+phi^6.....) and then solved.  Does this help?


LIAPP
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No. That is not relevant to what I asked.
292lu
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I don't agree with the answer to A posted here. It looks like you did 9/(1-.2^2) which would be the answer if it weren't an alternating series (i.e if it was 9*(1+.2^2+.2^4+...). However, this series is 9*(1+.2^2-.2^4+.2^6+...) I think, which shouldn't converge to the same value, right? I'm not sure if there is an exact formula for solving the alternating series, but I summed the first several terms and rounded and I get a different answer.

Edit: Never mind, I get it. Forgetting how to get a variance!

Edited 9 Years Ago by 292lu
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