TS Module 8: Non-stationary time series basics HW


TS Module 8: Non-stationary time series basics HW

Author
Message
NEAS
Supreme Being
Supreme Being (6K reputation)Supreme Being (6K reputation)Supreme Being (6K reputation)Supreme Being (6K reputation)Supreme Being (6K reputation)Supreme Being (6K reputation)Supreme Being (6K reputation)Supreme Being (6K reputation)Supreme Being (6K reputation)

Group: Administrators
Posts: 4.5K, Visits: 1.6K

TS Module 8: Non-stationary time series basics HW

(The attached PDF file has better formatting.)

Homework assignment: Stationarity through differencing and logarithms

Automobile liability claim severities have a geometric trend of +8% per annum.

The average claim severity in year t is the average claim severity in year t-1 adjusted for the geometric trend, plus or minus a random error term.

Assume the error term is added to the logarithm of the average claim severities.

The average claim severities are multiplied by a random error term.

 

Is the time series of average claim severities stationary?

Is the first difference of this time series stationary?

Is the second difference of this time series stationary?

Is the logarithm of this time series stationary?

What transformation makes the time series stationary?

Jacob:

What is the form of this time series?

Rachel:

Actuaries write: Yt = 1.08 Yt-1. The error term is multiplicative: Yt = 1.08 Yt-1 × (1 +

å).

A separate discussion forum posting shows the solution.


Attachments
Edited 14 Years Ago by NEAS
Reply
minnie53053
Junior Member
Junior Member (13 reputation)Junior Member (13 reputation)Junior Member (13 reputation)Junior Member (13 reputation)Junior Member (13 reputation)Junior Member (13 reputation)Junior Member (13 reputation)Junior Member (13 reputation)Junior Member (13 reputation)

Group: Forum Members
Posts: 11, Visits: 1
"....Jacob: What is the form of this time series?

Rachel: Actuaries write: Yt = 1.08 Yt-1. The error term is multiplicative: Yt = 1.08 Yt-1 × (1 + å)...."

What does mean the sentences above in the question?
We use Yt = 1.08 Yt-1 × (1 + å)as the times series in this question? but, I don't think it's right.
Even if the time series we should use is like that, both the first difference and the second difference are nonstationary, right? because:
D1(Yt)=0.08Y(t-1)+sigma(t) its mean is not constant. And,
D2(Yt+1)=(Yt+1-2*Yt+Yt-1), its mean is not constant also.

But from the text part 5.1, we can see the derivation results of first and second differences are stationary, so I can't be sure the results above are true.

Please help anybody.
GO
Merge Selected
Merge into selected topic...



Merge into merge target...



Merge into a specific topic ID...






Reading This Topic


Login
Existing Account
Email Address:


Password:


Social Logins

  • Login with twitter
  • Login with twitter
Select a Forum....





































































































































































































































Neas-Seminars

Search