TS Module 3 practice problems means and correlations


TS Module 3 practice problems means and correlations

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smh1021
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For Question 3.1, using the equation from page 28, does it solve to 1/200 because p1 = 0 since all of the terms are independent in a whilte noise process, meaning that the covariance is 0?

[NEAS: Yes]


char
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for 3.2, do the approximation and exact method (3.2.5 and 3.2.6) yield the same solution. I cant figure out the geometric sum?
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NEAS, the problem was solved using equation 3.2.6.  Please confirm whether this equation should be memorized for the Fall 2010 sitting.

[NEAS: The exercise shows the exact solution. The final exam problems can be solved by the approximation.]


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How did you solve using 3.2.5 since i'm getting [1/(1-0.5)] = 2 for the geometric series and not 3?
Michelle2010
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NEAS:

Do we need to know equation 3.2.6 for the final exam?  Module 3 says we will not be tested on it, however it is used in the solution to practice problem 3.2.

(I was able to solve the problem using equation 3.2.5, but I just want to make sure that we are not responsible for knowing equation 3.2.6.)

Thanks.


NEAS
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TS Module 3 Trends

 

(The attached PDF file has better formatting.)

 

Time series practice problems means and correlations

 

*Question 3.1: Var()

 

A white noise process Yt = åt has 200 observations, with ã0 = 1.

 

What is Var()?

 


A.     0.001

B.     0.002

C.    0.005

D.    0.010

E.     0.050

 

Answer 3.1: C

 

ã0 = ó2 = 1.

 

Var() = (1/200)2 × 200 × ó2 = 1/200 = 0.005

 

(See Cryer and Chan page 28)

 

Var( ) = (ã0 / n) × [(1 + 2 × ñ1 × (n-1)/n ] = 1/200 = 0.00500

 

 


 

*Question 3.2: Autoregressive process

 

A stationary time series Y of 300 observations has ñk = (½)|k| for all k and ã0 = 1.

 

What is Var()?

 


 

A.     0.01

B.     0.03

C.    0.05

D.    0.15

E.     0.30

 

Answer 3.2: A

 

Var() ≈

 

= (1.5)/(0.5) × 1/300 = 0.01000

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 


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