TS Module 3: Trends HW


TS Module 3: Trends HW

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NEAS
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TS Module 3: Trends HW

 

(The attached PDF file has better formatting.)

 

Homework assignment: MA(1) Process: Variance of mean

 

Five MA(1) processes with 50 observations are listed below. The variance of åt is 1.

 


A.     For each process, what is the variance of , the average of the Y observations?

B.     How does the pattern of the first time series differ from that of the last time series?

C.    Explain intuitively why oscillating patterns have lower variances of their means.

 

 


 

1.      Yt = ì + et + et-1

2.      Yt = ì + et + ½ et-1

3.      Yt = ì + et

4.      Yt = ì + et – ½ et-1

5.      Yt = ì + et – et-1


 

 

(See page 50 of the Cryer and Chan text, Exercise 3.2)

 

 


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TS Module 3 variance of mean HW.pdf (2.2K views, 32.00 KB)
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For process 5, Yt = mu + et - et-1

I use equation 3.2.3, I got result of 2/2500
But when I tried to do some simplification like exercise 3.2 on Page 50,
I got Var(~Y)=1/2500Var[(50.u + e50)], which gave me 1/2500 as result.

Im very confused and didnt see where I went wrong.
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